The function test for the blog

Never quit forever。

2019.2.13

又搞了一遍,测试下数学功能

$gi = \frac{i}{n}g_i + \frac {n-i}{n}g{i+1}+1$

$gi = g{i+1} + \frac{n}{n-i}​$

$fi = \frac{i}{n}(f_i+g_i+1) + \frac{n-i}{n}(f{i+1}+g_{i+1}+1)$

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